It is also known as the Fridrich Method after its popularizer, Jessica Fridrich. In part due to Fridrich’s publication of the method on her website in , CFOP has . If you have already read our beginner’s solution guide, you will already know how to do this step. But here are a few tips on how to get faster at. Then that means you probably only know how to solve the Rubiks Cube the easy way. Get fast with that puzzle and learn it the faster and more.

Author: Akinosho Akisho
Country: Brazil
Language: English (Spanish)
Genre: Medical
Published (Last): 4 July 2007
Pages: 144
PDF File Size: 12.64 Mb
ePub File Size: 6.4 Mb
ISBN: 121-2-39577-158-7
Downloads: 41645
Price: Free* [*Free Regsitration Required]
Uploader: Zololar

Every time you solve a pair, you are actually using the empty slot of that same pair. PLL Permutation of the Last Layer is where y ou permute move the pieces on the last layer to solve the entire cube.

The learning can seem long and hard, but do not give up. Here are the magic algorithms:.

With a bit of jdssica on all the cases, you should get closer to 10 seconds first two layers. You just need to count how many corners are not yellow on top.

How to Speedsolve the Rubik’s Cube – CFOP Method Explained

Memorizing them will save you time. To do that we will need to flip the corners and the edges.

Once you can do any cross blindfolded, you will be able to focus on the first pair while solving the cross. Look at your Rubik’s cube and try to see the optimal solution for solving the cross.


Policies and guidelines Contact us. From Wikibooks, open books for an open world. Either 2, 3 or 4 corners are incorrectly oriented. The cross is done intuitively. Either one face is completely finished or none is.

You want to learn the Fridrich but do you own a decent cube? You permute move the pieces on the last layer to solve the entire cube. Or do you feel like you need a better cube? If it is too difficult for you, maybe you can try it later on Orienting the last layer means putting all the yellow stickers on top. Every cross can be solved in under 10 moves. And this needs to be done while inserting them at the correct place.

Fridrich method : The fastest Rubik’s cube solution for 3x3x3

Once you are at that level, you should be able to solve every cross in under 1. Don’t worry if you don’t want learn all that yet.

Not turning the cube on this special case saves you about seconds. Most of the time, what slows you down is your inspection and your thinking. The Fridrich method is only made up of 4 steps but also full of algorithm to learn. I highly recommend learning this before you learn full OLL. Then then ones with two corners to orient and finished with the last two. Sometimes, it is easier to first build the pair and then insert it. However, you will need to spend a decent amount of time practising this step and the best way to do it is to solve it blindfolded.


OLL consists of 57 different algorithms. You already know the two formulas. We are now going to have a look at the Fridrich method. At first, we will do it in two steps: The basics are described in detail on our page which presents how to solve a Rubik’s cube. You solve a cross on top. They were used the one after the other in the step 7 of the beginners method. This moyu speed cube 3×3 comes pre-lubricated and tensioned.

I will show you the orientation of the last layer in two steps. Now you have everything to find the best F2L algorithms using Fridrich method. Also remember that you have two hands and the left hand should not only be used to hold the cube. Sometimes you can even take a minute to think on how to solve the cross. From these 3 cases, you should be able to deduce the entire solve. Advanced solution for Rubik’s cube 3×3 2 Fridrich method step 1: Using 2-look you can get sub easily so don’t feel you have to learn all the 57 algorithms yet.

If you don’t, you may break other pairs that have been already built before. It is the first step to the full Fridrich method, used by speedcubers. With a bit of practice, you left and right hands can solve cases equally as fast.